by Jenab » Tue 30 Aug 2005, 09:08:35
Titan is Saturn's largest moon. Its atmosphere is a mixture of nitrogen, argon and methane. Its surface is partially covered with complex organic liquids, probably including hydrocarbons that would be very burnable in an oxidizing atmosphere. The composition of those oceans might not be quite the same as that of our light, sweet crude oil, but they probably contain a roughly commensurate concentration of chemical energy.
But as far as using Titan's resources to benefit people on Earth goes, forget it. I'll explain why in a minute.
Titan's diameter is 3200 miles, meaning it's radius is 2,575,000 meters. It's surface area is 83.32 trillion square meters. If only one percent of Titan is covered by petroleum (or a similarly usable equivalent hydrocarbon) to a depth of only one meter, the volume of the stuff would be 833.2 billion cubic meters. There are 6.29 barrels (of oil) in a cubic meter, so 833.2 billion cubic meters is the same as 5.24 trillion barrels. That's between two and three times the amount of oil believed to have been in the Earth's crust before humans started pumping it out in the year 1859.
I'm going to assume that the mass density and the chemical energy density of Titan's hydrocarbons is the same as crude oil, 887 kilograms per cubic meter and 3.85E+10 Joules per cubic meter, respectively.
Titan's escape speed from surface is 2.64 km/sec. Boosting a cubic meter of hydrocarbon stuff from Titan's surface to free orbit around Saturn would require 3.09E+9 Joules (a bit more when you consider the mass of the cargo vessel). That's only 8% as much energy as is contained in the fuel. Further, boosting the hydrocarbons into low Titan orbit would cost only half as much energy, or only 4% of what the hydrocarbons contain. Power can be transmitted across considerable distances by maser.(1) Obviously, Titan could supply a human colony in the Saturn system with energy for centuries - if there were such a colony. What a pity there isn't.(2)
(1. Unfortunately, maser beams do spread, and it isn't possible to transmit power that way across interplanetary distances. )
(2. "Feeding the hungry" has apparently cost us the chance to create something of enduring worth beyond the confines of our planet. And it may be a chance lost to us forever.)
Now I'll explain why Titan's hydrocarbon seas won't help people on Earth. As you might expect, there's a thermodynamic problem: it costs more to transfer the cargo than can be recovered by burning the cargo.
The boost off Titan isn't a problem. The boost away from Saturn, provided that it is done with (not against) Titan's own orbital motion, isn't a problem either. Saturn's escape speed from Titan's orbital distance is 7.88 km/sec. Titan's orbital motion provides 5.58 km/sec of this speed, meaning that another boost of 2.3 km/sec will be required, which will cost 2.35E+9 Joules of energy. That's another 6.1% as much energy as I've assumed is contained in the cargo.
We're off Titan and clear of Saturn's gravity. It's possible that another 2.44 km/sec will be needed for insertion into the transfer orbit to Earth. Actually, it might be less than this if the boost away from Saturn is properly timed, but I'll be a pessimist. That's another 2.53E+9 Joules, or another 6.6% of the energy in the cargo.
So far, we've used up only 20.7% of the energy. An energy profit of almost four-fifths isn't bad. However, there's a nasty surprise ahead.
At the Earth end of the intended trajectory, the cargo vessel will be moving at 40 km/sec, relative to the sun. But we can aim the cargo vessel so that it reaches a rendezvous with Earth at a time when Earth's motion around the sun can be subtracted from the speed of the cargo vessel. Earth's average orbital speed is 29.8 km/sec, meaning that the cargo vessel will approach Earth, initially, at 10.1 km/sec.
That's the problem, or part of it. 10.1 km/sec is still mighty fast. If we try to slow down the cargo vessel with rockets, we'll end up using about three times as much energy as is contained in the oil - for that maneuver alone.
There's a clever astrophysicist's trick that can be played here. We can anticipate that we will rendezvous with Earth in low Earth orbit and expect to subtract from the incoming cargo vessel more kinetic energy (corresponding to the orbital speed in LEO) than it will gain by falling down the Earth's gravity well. But although this helps, it doesn't help enough. The cargo vessel will arrive in LEO moving at 15.1 km/sec, which is 7.3 km/sec too fast to remain in LEO. That 7.3 km/sec would need to be shed somehow, and shedding it with rockets would use up about 1.5 times more energy than the cargo contains.
Now, there's one more trick that might be playable, and that's slowing down the incoming cargo vessel with a mass-catcher, instead of with rockets. A mass-catcher is the reverse of a mass-driver. It uses magnetic induction to convert the kinetic energy of a metal (or metal-clad) object into electrical energy. The problem is, there's probably way too much kinetic energy in a cargo vessel weighing many tons and moving at 7.3 kilometers per second to be shed by any mass-catcher we're likely to be able to make. I'd expect that the result of trying it would be one hell of a big explosion in low Earth orbit, after which no oil, and no mass-catcher either.
So, no. Titan's hydrocarbons aren't going to save anyone on Earth.
Jerry Abbott
Last edited by
Jenab on Tue 30 Aug 2005, 09:28:25, edited 1 time in total.