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energy loss reduction through a vacuum

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energy loss reduction through a vacuum will this ever happen?

Poll ended at Thu 23 Mar 2006, 00:50:46

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Re: 'Vacuum' Energy devices - the MEG

Unread postby Markos101 » Sat 10 Jun 2006, 18:15:31

Bearden indicates that if you observe E = -dA/dt, you may create an electric field by varying the B field and hence the A field. Thus by having a secondary 'output' coil, this E-field may be harnessed and used to 'energize' electrons in the output coil rather like a current. The current in the input coil may be pulsed hence, if the input pulses are almost in a tophat-like fashion, you may produce a large dA/dt and hence large E field, with no B field component associated with the A field outside of the solenoid.

You don't have to put any extra energy into the input coil to do this, as the A field outside of the solenoid is a quantum effect that appears via gauge freedom, which Bearden claims is explained by quantum electrodynamics (the quantum version of classical EM) via the vacuum being occupied by virtual particles, including the virtual photons reponsible for interactions of electrons.

I've just received his book, 'Energy from the Vacuum' today through the post from the US, which I'm giving a read. I'm actually surprisingly optimistic and I'll probably be talking to the old profs in my former Uni about this.
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Re: 'Vacuum' Energy devices - the MEG

Unread postby skeptic » Sat 10 Jun 2006, 18:30:31

$this->bbcode_second_pass_quote('Markos101', '
')I've just received his book, 'Energy from the Vacuum' today through the post from the US, which I'm giving a read. I'm actually surprisingly optimistic and I'll probably be talking to the old profs in my former Uni about this.


I have no way of judging the science, but by judging the man and his methods I'd say Bearden is just another mad old scammer on the make.

He's been threatening to put the MEG into production for years, and forever coming up with excuses why he hasnt.. just a few more dollars to finish off the development always seeem to be lacking.

The proof of the pudding is in the eating. I'll believe it when I can buy one in Currys or Argos, and plug my telly into it. till then I'd suggest his MO suggests that hes not worth wasting any time on. He stinks of fraud. I bet your old profs tell you he's talking shite.

"Association of Distinguished American Scientists (ADAS)"
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Re: 'Vacuum' Energy devices - the MEG

Unread postby emailking » Sat 10 Jun 2006, 20:41:50

$this->bbcode_second_pass_quote('Markos101', 'B')earden indicates that if you observe E = -dA/dt, you may create an electric field by varying the B field and hence the A field. Thus by having a secondary 'output' coil, this E-field may be harnessed and used to 'energize' electrons in the output coil rather like a current. The current in the input coil may be pulsed hence, if the input pulses are almost in a tophat-like fashion, you may produce a large dA/dt and hence large E field, with no B field component associated with the A field outside of the solenoid.

You don't have to put any extra energy into the input coil to do this, as the A field outside of the solenoid is a quantum effect that appears via gauge freedom, which Bearden claims is explained by quantum electrodynamics (the quantum version of classical EM) via the vacuum being occupied by virtual particles, including the virtual photons reponsible for interactions of electrons.

I've just received his book, 'Energy from the Vacuum' today through the post from the US, which I'm giving a read. I'm actually surprisingly optimistic and I'll probably be talking to the old profs in my former Uni about this.


Certainly you can make an Electric field by varying the current (and thus the magnetic field) in the solenoid. But in the static situation, there is no electric field.
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Re: 'Vacuum' Energy devices - the MEG

Unread postby Markos101 » Sun 11 Jun 2006, 09:13:15

I agree there are suspicions perhaps over the length of development, but the backing physics appears to agree with experiement. You do indeed produce an E field by pulsing the magnetude of an A field, and indeed you do obtain an A-field outside of a solenoid in a region in which there is no B field.

But it would nice to see a working model.
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Re: 'Vacuum' Energy devices - the MEG

Unread postby Caoimhan » Mon 12 Jun 2006, 09:50:45

$this->bbcode_second_pass_quote('emailking', '')$this->bbcode_second_pass_quote('Caoimhan', '')$this->bbcode_second_pass_quote('emailking', '')$this->bbcode_second_pass_quote('Caoimhan', '
')
One group in Switzerland is running 5 of these machines and powering their communes with them.


Ok, what is the evidence for this?


http://energy21.freeservers.com/testimages.htm


Yeah, I was expecting something a little more convincing. Like some articles. Obviously, there are plenty of crackpot websites out there.


Review the links at the bottom of the page then. Of particular note is the 1999 demonstration they did for a group of engineers.
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Re: 'Vacuum' Energy devices - the MEG

Unread postby small_steps » Fri 16 Jun 2006, 22:43:22

$this->bbcode_second_pass_quote('emailking', 'I')f you draw a loop in the right place you can have a flux, yes. This has nothing to do with the elctron deflecting. If your loop is constant, the flux is not changing because the field inside the solenoid is constant. So there are no electric fields created. And we already no there are no magnetic fields. If the elctrong deflects, than one or the other would have to be responsible classically.


I have to come back to electric machines...

Take a permanent magnet machine (that is you have static magnetic flux source on the rotor), lock the rotor mechanically (so you don't have a change in flux vs time), and send a constant current through one of the windings. Now if this is a fairly well designed machine, there should be negligable magnetic flux in the winding (from the magnet). Yet we will still observe a torque. The magnetic flux is constant, there is a constant electric field in the winding, and the winding is effectively shielded from the magnetic flux from the magnet (by the stator teeth). Now if you remove the magnet, and therefore the magnetic flux (and have a symmetric rotor), and inject a constant current, you will no longer discern a torque.

Does this make sense? And does what I describe sound a bit like the A-B effect?
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